Formula: C3H7I
Answer: Isopropyl Iodide (2-iodopropane)
Chemical Shift Assignments:
The two methyl groups are enantiotopic and necessarily equivalent. The 13C spectrum shows two peaks: 31.3 and 21.2 ppm. Which singlet is the methyl carbon? Click here. The six protons at δ 1.90 split the methine proton at δ 4.32 into a septuplet. Conversely, the methine proton splits the methyl groups into a doublet. There is a weak doublet at δ1.13 and an even weaker one at δ 1.23. Blow-up this region. What do you think the signal at δ 1.13 might be? How might this sample of isopropyl iodide been made? Try the next spectrum. Return to Menu.
![]() |
iodine=violet |
---|