Formula: C₈H₁₄O₄

Answer: Diethyl succinate

Chemical Shift Assignments:

¹H NMR: δ 1.21 (t, 3H, J = 7 Hz), 2.56 (2H, s), and 4.10 (2H, quartet, 1H, J = 7 Hz)

¹³C NMR: 172.2, 60.3, 29.0, and 14.0 ppm

The formula indicates two degree of unsaturation. The integration is half the number of hydrogens in the ¹H NMR integration. Moreover, the ¹³C spectrum reveals only four carbons. Symmetry is present. The signals at δ 1.21 and 4.10 in the ¹H NMR spectrum comprise an ethyl pattern with an attachment to a heteroatom-- namely, oxygen. The ¹³C NMR signal at 172.2 ppm indicates an ester. Thus, there are two -C(O)OC₂H₅ groups. All that is left to the formula is the two methylene groups at δ 2.56. Return to Menu.